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Find: The 10th term of the G.P. \(-\frac{3}{4}, \frac{1}{2}, -\frac{1}{3}, \frac{2}{9}\).... |
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Answer» Tn = arn-1 a = \(\frac{-3}{4}\), r = \(\cfrac{\frac{1}{2}}{\frac{-3}{4}}\) = \(\frac{-2}{3}\) \(\therefore\) T9 = \(\frac{-3}{4}(-\frac{2}{3})^{10-1}\) = \(\frac{-3}{4} \times \frac{-2^9}{3^9}\) = \(\frac{2^7}{3^8}\) \(\therefore\) The 10 Term is \(\frac{2^7}{3^8}\) |
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