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Find the 12th term from the end of the arithmetic progressions:3, 5, 7, 9, …. 201 |
Answer» Given A.P = 3, 5, 7, 9, …. 201 Here, a = 3 and d = (5 – 3) = 2 Now, find the number of terms when the last term is known i.e, 201 an = 3 + (n – 1)2 = 201 3 + 2n – 2 = 201 2n = 200 n = 100 Hence, the A.P has 100 terms. So, the 12th term from the end is same as (100 – 12 + 1)th of the A.P which is the 89th term. ⇒ a89 = 3 + (89 – 1)2 = 3 + 88(2) = 3 + 176 = 179 Therefore, the 12th term from the end of the A.P is 179. |
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