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Find the 23rd term of the AP 7, 3, 1, –1, –3, … |
Answer» To Find: 23rd term of the AP Given: The series is 7, 5, 3, 1, –1, –3, … a1 = 7, a2 = 5 and d = 3–5 = –2 (Where a = a1 is first term, a2 is second term, an is nth term and d is common difference of given AP) Formula Used: an = a + (n - 1)d So put n = 23 in above formula, we have a23= a1 + (23 - 1)(–2) = 7– 44 = –37 So 23rd term of AP is equal to –37. |
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