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Find the 4th term from the end of the G.P. 2/27, 2/9, 2/3, …., 162. |
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Answer» The nth term from the end is given by: an = l (1/r)n-1 where, l is the last term, r is the common ratio, n is the nth term Given: last term, l = 162 r = t2/t1 = (2/9) / (2/27) = 2/9 × 27/2 = 3 n = 4 So, an = l (1/r)n-1 a4 = 162 (1/3)4-1 = 162 (1/3)3 = 162 × 1/27 = 6 ∴ 4th term from last is 6. |
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