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Find the amount of Rs. 10000 after 2 years compounded annually; the rate of interest being 10% per anum during the first year and 12% per annum during the second year. Also, find the compound interest. |
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Answer» Present value = Rs.10000 Interest rate for 1st year, p = 10 % per annum Interest rate for 2nd year, q = 12 % per annum Time = 2 years Amount (A) = P × (1 + p/100) × (1 + q/100) A = 10000 × (1 + 10/100) × (1 + 12/100) = 10000 × (1 + 1/10) × (112/100) = 10000 × 11/10 × 112/100 = 10 × 11 × 112 = 12320 ∴ Amount = Rs.12320 ∴ Compound interest = Rs.(12320 – 10000) = Rs.2320 |
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