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Find the angle between the vector 4i+3j-4k and 3i +4k+6j |
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Answer» Answer: 90 degrees Explanation: (root 16+9+16 )(root 9+16+36) cos theeta =4*3+3*4-4*6 cos theeta=12+12-24/(root 16+9+16 )(root 9+16+36) cos theeta =0 thus theeta =90 |
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