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Find the AP whose 3rd term is -13 and 6th term is 2. |
Answer» Let a be the first term and d be the common difference. Now, a3=-13 => a + 2d = -13 ---------(1) now, a6 = 2 => a + 5d = 2 -----------(2) Subtracting (1) from (2) we get 5d-2d = 2+13 3d = 15 d = 5 Now, from equation (1) we get a = -13 - 2x5 = -23 The required A.P is given by a, a+d, a+2d, ........... So, A.P is -23, -18, -13, -8, -3, 2,...... |
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