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Find the approximate value of \(\sqrt{49.1}\).(a) 7.0142(b) 7.087942(c) 7.022(d) 7.00714I had been asked this question during an interview.My question is based upon Derivatives Application topic in division Application of Derivatives of Mathematics – Class 12

Answer»

Correct option is (d) 7.00714

Easiest EXPLANATION: Let y=\(\sqrt{49.1}\). Let x=49 and Δx=0.1

Then, Δy=\(\sqrt{x+Δx}-\sqrt{x}\)

 Δy=\(\sqrt{49.1}-\sqrt{49}\)

\(\sqrt{49.1}\)=Δy+7

dy is approximately EQUAL to Δy is equal to

dy=\(\FRAC{dy}{dx}\)Δx

dy=\(\frac{1}{(2\sqrt{x})}\).Δx

dy=\(\frac{1}{(2\sqrt{49})}\) (0.1)

dy=0.1/14=0.00714

∴ The approximate VALUE of \(\sqrt{49.1}\) is 7+0.00714=7.00714



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