Find the area of Fig. as the sum of the areas of two trapezium and a

1.	Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.
Answer» Area of figure = Area of two trapeziums + area of rectangle Length of rectangle = 50 cm Breadth of rectangle = 10 cm Length of parallel sides of trapezium = 30 cm and 10 cm Distance between parallel sides of trapezium = \(\frac{70-50}{2}\) = \(\frac{20}{2}\) = 10 cm Area of figure = 2 x \(\frac{1}{2}\)(sum of sides) x distance between parallel sides + length x breadth Area of figure = 2 × \(\frac{1}{2}\)(30 + 10) x 10 + 50 x 10 Area of figure = 400 + 500 = 900 cm²

Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.

Answer»

Area of figure = Area of two trapeziums + area of rectangle

Length of rectangle = 50 cm

Breadth of rectangle = 10 cm

Length of parallel sides of trapezium = 30 cm and 10 cm

Distance between parallel sides of trapezium = \(\frac{70-50}{2}\) = \(\frac{20}{2}\) = 10 cm

Area of figure = 2 x \(\frac{1}{2}\)(sum of sides) x distance between parallel sides + length x breadth

Area of figure = 2 × \(\frac{1}{2}\)(30 + 10) x 10 + 50 x 10

Area of figure = 400 + 500 = 900 cm²