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Find the area of the parallelogram whsoe adjacent sides are given by the vectors `veca=hati-hatj+3hatk dn vecb=2hati-7hatj+hatk`` |
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Answer» The area of the parallelgram whose adjacent sides are `veca and vecb is |veca xx vecb|` Adjacent sides are given as `veca=hati-hatj+3hatkand vecb=2hati-7hatk+hatk` `vecaxxvecb=|{:(hati,hatj,hatk),(1,-1,3),(2,-7,1):}|=hati(-1+21)-hatj(1-6)+hatk(-7+2)=20hati=5hatj-5hatk` `|vecaxxvecb|=sqrt(20^(2)+5^(2)+(-5)^(2))=sqrt(400+25+25)=15sqrt2` Hence, the area of the given parllelogram is `15sqrt2` square units. |
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