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Find the binding anergy of an electron in the ground state of a hydrogen like atom in whose spectrum the thrid Balmer line is equal to 108.5 mm.A. `54.4 eV`B. `13.6 eV`C. `112.4 eV`D. None of these |
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Answer» Correct Answer - A `Delta E = (12375)/(1085) = 11.4 eV` Third Balmer line is corresponding to the transition, n =5 to n =2 `E_5 - E_2 =11.4` `:. (E_1)/((5))^2 - (E_1)/((2))^2 11.4` `E_1=-54.28 eV` `:. |E_1| = 54.28 eV.` |
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