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Find the centre and radius of the circle `3x^(2) 3y^(2) - 6x +9y - 8 =0`. |
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Answer» `3x^(2)+3y^(2)-69y-8=0` `rArrx^(2)+y^(2)-2x+3y-(8)/(3)=0` Comparing with the general equation of the circle `x^(2)+y^(2) +2gx +c =0` `2g=-2,2f=3 and c=-(8)/(3)` `rArrg=-1,f=(3)/(2)and c=-(8)/(3)` `:.` Centre of circle `= (-g,-f)` `= (1,-(3)/(2))` And radius of circle `=sqrt(g^(2)+f^(2)-c)=sqrt(1+(9)/(4)-(-(8)/(3)))` `=sqrt(1+(9)/(4)+(8)/(3))=sqrt((12+27+32)/(12))` `= sqrt((71)/(12))=(sqrt(71))/(2sqrt(3))` units. |
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