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Find the centre and radius of the circle `(x+2)^(2)+(y+3)^(2)=5` |
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Answer» `(x+2)^(2)+(y+3)^(2)=5` `rArr(x+2)^(2)+(y+3)^(2)=(sqrt(5))^(2)` Comparing with the equation of the circle `(x-h)^(2)+(y-k)^(2)=a^(2)` `h=-2,k=-3,a=sqrt(5)` `:.` Centre of circle `=(h,k) =(-2,-3)`, and radius `a= sqrt(5)`. |
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