1.

Find the centre and radius of the circles`2x^2+2y^2-x=0`

Answer» `2x^(2)+2y^(2)-x=0`
`rArrx^(2)+y^(2)-(1)/(2)x=0`
Comparing with `x^(2)+y^(2)+2gx+2fy+c=0`
`2g=-(1)/(2),2f=0,c=0`
`rArr""g=-(1)/(4),f=0,c=0`
`:. "Centre of circle"-=(-g,-f)-=((1)/(4),0)`
and radius `=sqrt(g^(2)+f^(2)-c)`
`=sqrt((-(1)/(4))^(2)+0-0=(1)/(4))` unit


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