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Find the centre and radius of the circles`2x^2+2y^2-x=0` |
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Answer» `2x^(2)+2y^(2)-x=0` `rArrx^(2)+y^(2)-(1)/(2)x=0` Comparing with `x^(2)+y^(2)+2gx+2fy+c=0` `2g=-(1)/(2),2f=0,c=0` `rArr""g=-(1)/(4),f=0,c=0` `:. "Centre of circle"-=(-g,-f)-=((1)/(4),0)` and radius `=sqrt(g^(2)+f^(2)-c)` `=sqrt((-(1)/(4))^(2)+0-0=(1)/(4))` unit |
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