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Find the centre and radius of the circles`x^2+y^2-4x-8y-45=0` |
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Answer» `x^(2)+y^(2)-4x-8y-45=0` Comparing with `x^(2)+y^(2)+gx+2fy+c=0` `2g=-4,2f=-8,c=-45` `rArr" "g=-2,f=-4,c=-45` `:.` Centre of circle `-=(-g,-f)-=(2,4)` and radius `r=sqrt(g^(2)+f^(2)-c)` `=sqrt((2)^(2)+(4)^(2)-(-45))` `sqrt(4+16+45)=sqrt(65)` units |
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