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Find the centre and radius of the circles`(x+5)^2+(y-3)^2=36` |
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Answer» `(x+5)^(2)+(y-3)^(2)=36` Comparing with `(x+5)^(2)+(y-k)^(2)=r^(2)` `h=-5,k=3,r^(2)=36` `rArr" "h=-5,k=3,r=6` `:.` Centre of circle `-=(h,k)-=(-5,3)` and radius = 6 units |
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