1.

Find the centroid of the triangle whose vertices are A(-1,0), B(5, -2) and C(8, 2).

Answer»

Solution :Centroid, the point where the medians ofa triangle intersect, divides each MEDIAN in the ratio 2:1. Let AD be the median and G(x, y) be the centroid of `DeltaABC`.
`thereforeD` is the mid-point of BC.
`therefore" "D-=((5+8)/(2),(-2+2)/(0))""` (mid-point formula)
`""-=((13)/(2),0)`

Now, G(x, y) divides the line segment JOINING A(-1,0) and `D((13)/(2),0)` internally in the ratio 2 : 1.
So, by USING section formula,
`""x=(2((13)/(2))+1(-1))/(2+1)" "rArr" "x=4`
and `""y=(2(0)+1(0))/(2+1)" "rArr" "y=0`
`therefore` Centroid of `DeltaABC-=` (4, 0)


Discussion

No Comment Found

Related InterviewSolutions