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    				| 1. | Find the common ratio of the GP whose first and last terms are 25 and `(1)/(625)` respectively and the sum of the GP is `(19531)/(625)`. | 
| Answer» We know that the sum of a GP is `("first term" - r("last term"))/(1-r)` or `(19531)/(625) = (25-((r )/(625)))/(1-r)` `therefore r= (1)/(5)` | |