1.

Find the common ratio of the GP whose first and last terms are 25 and `(1)/(625)` respectively and the sum of the GP is `(19531)/(625)`.

Answer» We know that the sum of a GP is `("first term" - r("last term"))/(1-r)`
or `(19531)/(625) = (25-((r )/(625)))/(1-r)`
`therefore r= (1)/(5)`


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