Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{25})^2\)=1.(a) (±3,0)(b) (±4,0)(c) (0,±3)(d) (0,±4)I got this question during a job interview.This intriguing question originated from Conic Sections in division Conic Sections of Mathematics – Class 11

Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{2

1.	Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{25})^2\)=1.(a) (±3,0)(b) (±4,0)(c) (0,±3)(d) (0,±4)I got this question during a job interview.This intriguing question originated from Conic Sections in division Conic Sections of Mathematics – Class 11
Answer» The CORRECT option is (c) (0,±3) To explain I would SAY: Comparing the equation with \((\frac{x}{b})^2+(\frac{y}{a})^2\)=1, we GET a=5 and b=4. For ellipse, c^2=a^2-b^2=25-16=9 => c=3. So, COORDINATES of foci are (0,±c) i.e. (0,±3).

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