Find the coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.(a) (±3,0)(b) (±4,0)(c) (0,±3)(d) (0,±4)The question was posed to me at a job interview.I need to ask this question from Conic Sections in section Conic Sections of Mathematics – Class 11

Find the coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{1

1.	Find the coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.(a) (±3,0)(b) (±4,0)(c) (0,±3)(d) (0,±4)The question was posed to me at a job interview.I need to ask this question from Conic Sections in section Conic Sections of Mathematics – Class 11
Answer» Correct answer is (a) (±3,0) Best explanation: Comparing the equation with \((\FRAC{x}{a})^2+(\frac{y}{b})^2\)=1, we GET a=5 and b=4. For ellipse, c^2=a^2-b^2=25-16=9 => c=3. So, COORDINATES of foci are (±c,0) i.e. (±3,0).

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