Find the coordinates of foci of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1.(a) (±5,0)(b) (±4,0)(c) (0,±5)(d) (0,±4)The question was posed to me by my college professor while I was bunking the class.I need to ask this question from Conic Sections in division Conic Sections of Mathematics – Class 11

Find the coordinates of foci of hyperbola \((\frac{x}{9})^2-(\frac{y}{

1.	Find the coordinates of foci of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1.(a) (±5,0)(b) (±4,0)(c) (0,±5)(d) (0,±4)The question was posed to me by my college professor while I was bunking the class.I need to ask this question from Conic Sections in division Conic Sections of Mathematics – Class 11
Answer» Right option is (a) (±5,0) The BEST I can explain: Comparing the equation with \((\frac{x}{a})^2-(\frac{y}{B})^2\)=1, we GET a=3 and b=4. For hyperbola, c^2=a^2+b^2=9+16=25 => c=5. So, coordinates of FOCI are (±c,0) i.e. (±5,0).

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