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Find the coordinates of foci of hyperbola \((\frac{y}{16})^2-(\frac{x}{9})^2\)=1.(a) (±5,0)(b) (±4,0)(c) (0,±5)(d) (0,±4)I have been asked this question in semester exam.This question is from Conic Sections in portion Conic Sections of Mathematics – Class 11

Answer»

The correct option is (C) (0,±5)

For explanation: Comparing the equation with \((\frac{y}{a})^2-(\frac{x}{B})^2\)=1, we get a=4 and b=3.

For hyperbola, c^2=a^2+b^2= 16+9=25 => c=5.

So, coordinates of FOCI are (0,±c) i.e. (0,±5).



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