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Find the coordinates of the foci, the vertices, the eccentricity and the length of the latus rectum of the Hyperbola `16x^(2)-9y^(2)=576` |
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Answer» Equation of hyperbola `16x^(2)-9y^(2)=576` `rArr(x^(2))/(36)-(y^(2))/(64)=1` `:.` The transverse axis of hyperbola is along x-axis. Comparing with `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` `a^(2)=36," "b^(2)=64` `rArr" "a=6," "b=8` `:. "Vertices" -=(pma,0)-=(pm6,0)` Eccentricity `e=sqrt(1+(b^(2))/(a^(2)))=sqrt(1+(64)/(36))` `=sqrt((100)/(36))=(10)/(6)=(5)/(3)` Now, ae `=6xx(5)/(3)=10` `:. "Coordinates of foci" -=(pmae,0)=(pm10,0)` Length of latus rectum `=(2b^(2))/(a)` `=(2xx(8)^(2))/(6)=(64)/(3)` |
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