1.

Find the cost of plastering the inner surface of a well at Rs. 9.50 per m2, if it is 21 m deep and diameter of its top is 6 m.

Answer»

Given,

Height of cylinder = 21 m

Diameter of cylinder = 6 m

Radius of cylinder = \(\frac{6}{2}\) = 3 m

So,

Curved surface area of cylinder = 2πrh = 2 x \(\frac{22}{7}\) x 3 x 21 = 396 m2

∴ Cost of plastering the inner surface at rate Rs.9.50 per m2 = 396 × 9.50 = Rs. 3762



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