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Find the current through (5+j4) Ω resistor.(a) 0.9-j0.2 A(b) 0.78-j0.1 A(c) 2.7-j0.5 A(d) 1AThis question was addressed to me at a job interview.This interesting question is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct answer is (a) 0.9-j0.2 A

To elaborate: 1. Remove the 5+j4 Ω branch and calculate THEVENIN’s voltage.

(V= v across 6Ω RESISTOR- v across 8Ω resistor)

2. Calculate Zth. (10//6 and 8//8)

3. Current= (VTH/ (Zth+Z).



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