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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Superposition principle states that at a time __________ source(S) acts.(a) All the given sources(b) Only voltage sources(c) Only one source(d) Only current sourcesThe question was posed to me by my school principal while I was bunking the class.Question is taken from Maximum Power Transfer and Superposition topic in chapter Techniques of Circuit Analysis of Electric Circuits

Answer»

Right choice is (c) Only ONE source

The best I can explain: Only one source ACTS at a TIME. Remaining sources are non-operative during this PERIOD.

2.

Calculate the maximum power delivered to load in the network given.(a) 1.56W(b) 1.66W(c) 2.33W(d) 2.79WThe question was posed to me by my college director while I was bunking the class.The query is from Maximum Power Transfer and Superposition topic in section Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT CHOICE is (a) 1.56W

To explain I WOULD say: 1.Calculation of VTh. (by using mesh analysis)

2. Calculation of Norton’s current.

3. Calculation of RTh. (RTh=VTh/IN)

4. RTh=RL and PMax= VTh/4RL.
3.

In AC networks, maximum power is delivered when__________(a) ZL*ZS*=0(b) ZL+ZS*=1(c) ZL=-ZS*(d) ZL=ZS*I have been asked this question in an international level competition.The doubt is from Maximum Power Transfer and Superposition topic in chapter Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT choice is (d) ZL=ZS*

Explanation: Max power is delivered when LOAD IMPEDANCE equals COMPLEX CONJUGATE of the source impedance.
4.

Find the value of RL in given circuit.(a) 4Ω(b) 5Ω(c) 3Ω(d) 1.66ΩThis question was addressed to me in quiz.This is a very interesting question from Maximum Power Transfer and Superposition in portion Techniques of Circuit Analysis of Electric Circuits

Answer» RIGHT ANSWER is (C) 3Ω

Easiest EXPLANATION: RTh=RL= (2//2) + 2=3Ω.
5.

Find the current in the 1Ω resistor of the given circuit.(a) 4A(b) 1.33A(c) 2A(d) 0.66AI had been asked this question in final exam.Origin of the question is Maximum Power Transfer and Superposition in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

Right answer is (a) 4A

To EXPLAIN I would SAY: when all the SOURCES are acting alone the corresponding CURRENTS are found out using current division rule and FINALLY all are summated to get the required current through the1Ω resistor. (Current = 1.33+0.66+2=4A).

6.

If there are 5 sources in a network out of which 3 are dependent and 2 are independent. For superposition principle ___________ sources are considered.(a) 5(b) 3(c) 2(d) 0This question was addressed to me during an internship interview.This interesting question is from Maximum Power Transfer and Superposition in division Techniques of Circuit Analysis of Electric Circuits

Answer»

The correct answer is (c) 2

Explanation: Only independent sources are CONSIDERED while using SUPERPOSITION principle. Dependent sources are NEVER deactivated while using this principle.

7.

Find the current in 5Ω resistor near 12V source using superposition principle in network given(a) 2.9A(b) -2.9A(c) 1A(d) -1AI got this question in a national level competition.The origin of the question is Maximum Power Transfer and Superposition in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Right option is (b) -2.9A

For EXPLANATION I would say: Only 3 sources are CONSIDERED (12V, 10A, 20V), other is dependent (10I).

 12v source: I=0.6A

10A source: I=-2.5A through 5Ω resistor and I=7.5A

20v source: I=-1A

Total CURRENT = 0.6+ (-2.5) + (-1) = -2.9A.

8.

Find the current in the 3Ω resistor of the given network using Superposition principle.(a) 2.5A(b) 3.125A(c) 6.525A(d) 5.625AI had been asked this question in homework.This is a very interesting question from Maximum Power Transfer and Superposition in division Techniques of Circuit Analysis of Electric Circuits

Answer»

The correct choice is (d) 5.625A

To elaborate: 1.When 20v SOURCE acting alone: CURRENT source is REPLACED by open CIRCUIT.Req= 5+3=8Ω and Current I= 20/8=2.5A

2. When 5A source acting alone: 20v source is replaced by a short circuit. By current DIVISION rule, I3= 25/8=3.125A

Total current through I3= 2.5+3.125=5.625A.

9.

According to Superposition principle response in one element is the algebraic sum of responses by individual sources acting alone.(a) False(b) TrueThe question was posed to me during an internship interview.I would like to ask this question from Maximum Power Transfer and Superposition in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Right answer is (b) True

Explanation: According to SUPERPOSITION PRINCIPLE response in one element is the ALGEBRAIC SUM of responses by individual sources ACTING alone while other sources are non-operative.

10.

The Superposition principle is obeyed by ____________(a) Linear networks(b) Non-linear networks(c) Lateral networks(d) Trilateral networksI have been asked this question in quiz.This is a very interesting question from Maximum Power Transfer and Superposition in section Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT choice is (a) Linear networks

To ELABORATE: A linear system obeys Superposition Principle. In a linear NETWORK PARAMETERS are constant i/e/ won’t CHANGE with voltage and current.
11.

Determine the maximum power delivered to the load in the network given.(a) 4.68W(b) 5.75W(c) 3.16W(d) 6.84WThe question was posed to me in examination.This interesting question is from Maximum Power Transfer and Superposition in chapter Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct choice is (a) 4.68W

To elaborate: Load is given across node V2 and reference path. It implies the THEVENIN’s voltage is V2. By USING NODAL ANALYSIS this voltage is found out.

RTh=RL= 10Ω//5Ω and in series with 2Ω and then parallel with 3Ω=1.92Ω

Max power = (VTh)^ 2 /4RL = 4.688W.

12.

Calculate the maximum power delivered across RL of the circuit given.(a) 900W(b) 1025W(c) 2025W(d) 1500WThe question was posed to me during an internship interview.This interesting question is from Maximum Power Transfer and Superposition topic in division Techniques of Circuit Analysis of Electric Circuits

Answer»

The correct choice is (C) 2025W

The explanation is: Pmax= (VTh/(RTh+RL))^2*RL(RTh=RL)

VTh= (150/150+30)*540= 450V

RTh=(150*30)/180= 25Ω (the GIVEN resistors are in parallel).

13.

Maximum power in terms of the thevenin’s voltage and load resistance __________(a) (VTh) 2 /4RL(b) (VTh) 2 *4RL(c) (VTh) 2 +4RL(d) 4RL/ (VTh) 2The question was asked in exam.This is a very interesting question from Maximum Power Transfer and Superposition in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Right choice is (a) (VTH) 2 /4RL

For explanation: PMAX= V*i= i*R*i= i2RL = (VTh/(RTh+RL))2*RL.Max power occurs when RL=RTh.

14.

In a network maximum power transfer occurs when __________(a) RTh= -RL(b) RTh/RL =0(c) RTh= RL(d) RTh+RL= 1This question was posed to me in an interview for job.The question is from Maximum Power Transfer and Superposition in chapter Techniques of Circuit Analysis of Electric Circuits

Answer»

Right CHOICE is (c) RTh= RL

The EXPLANATION is: Maximum POWER transfer OCCURS when load resistance equals the thevenin’s resistance.

15.

Which of the following is the example to describe the efficiency of power transfer?(a) Communication systems(b) Power utility systems(c) Instrumentation systems(d) Telecom systemsThis question was addressed to me in an interview for job.This is a very interesting question from Maximum Power Transfer and Superposition in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Right option is (B) Power utility systems

Easiest explanation: Power utility systems are good examples for this CASE as they are concerned with the generation, transmission and DISTRIBUTION of power in LARGE quantities.

16.

One can find the thevenin’s resistance simply by removing all voltage/current sources and calculating equivalent resistance.(a) False(b) TrueThe question was asked during an interview for a job.My doubt is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Right choice is (B) True

For explanation I WOULD say: Yes. ONE can FIND the thevenin’s resistance simply by removing all voltage/current sources and calculating equivalent resistance.

17.

What is the expression forthe thevenin’s current if there is an external resistance in series with the RTh?(a) VTh/ITh(b) VTh/ (RTh-R)(c) VTh/ (RTh+R)(d) VTh/RThI have been asked this question in an internship interview.This question is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent in portion Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT ANSWER is (C) VTH/ (RTh+R)

Explanation: ITh= VTh/ (RTh+R).
18.

Thevenin’s resistance RTh = ___________(a) VTh/ISC(b) VSC/ITh(c) VTh/ITh(d) VSC /ISCI have been asked this question during an online interview.My doubt is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent in portion Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT CHOICE is (a) VTh/ISC

Explanation: THEVENIN’s resistance is defined as the ratio of open circuit voltage to the short circuit current ACROSS the terminals of the original circuit.
19.

Norton’s current is equal to ____________(a) Short circuit voltage(b) Open circuit current(c) Open circuit voltage(d) Short circuit currentI got this question in semester exam.The origin of the question is Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in chapter Techniques of Circuit Analysis of Electric Circuits

Answer»

The correct CHOICE is (d) SHORT circuit CURRENT

Best explanation: Norton’s current is EQUAL to Short circuit current.

20.

Thevenin’s voltage is equal to ____________(a) Short circuit voltage(b) Open circuit current(c) Open circuit voltage(d) Short circuit currentThe question was posed to me in exam.Asked question is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in division Techniques of Circuit Analysis of Electric Circuits

Answer» RIGHT OPTION is (c) Open circuit voltage

The EXPLANATION: Thevenin’s voltage is EQUAL to open circuit voltage.
21.

Norton’s equivalent circuit consists of a _____________(a) Voltage source in series with a resistor(b) Current source in parallel with a resistor(c) Both voltage and current sources(d) Current source in series with a resistorThis question was addressed to me in homework.My doubt is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

Right choice is (b) CURRENT source in parallel with a resistor

The BEST explanation: Norton’s equivalent circuit consists of a Current source in parallel with a resistor.

22.

Thevenin’s equivalent circuit consists of a ____________(a) Voltage source in series with a resistor(b) Current source in parallel with a resistor(c) Voltage source in parallel with a resistor(d) Current source in series with a resistorThis question was posed to me by my college director while I was bunking the class.This intriguing question comes from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in section Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT choice is (a) Voltage SOURCE in series with a RESISTOR

Best EXPLANATION: Thevenin’s equivalent CIRCUIT contains a Voltage source in series with a resistor.
23.

Calculate RTh for the network given.(a) 8Ω(b) 7Ω(c) 2Ω(d) 1ΩI had been asked this question during a job interview.Enquiry is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in portion Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT OPTION is (B) 7Ω

Explanation: 5//20 and then in SERIES with 3Ω RESISTOR.
24.

Find the Norton’s current for the circuit given below.(a) 5A(b) 3.33A(c) 4A(d) 1.66AI have been asked this question in exam.Origin of the question is Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent in chapter Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT CHOICE is (C) 4A

For EXPLANATION: IN= (20/10) + (10/5).
25.

Calculate IN for the given network.(a) 0A(b) 1A(c) 4.37A(d) 0.37AThe question was asked in class test.This interesting question is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent in portion Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT OPTION is (a) 0A

The EXPLANATION is: Using nodal ANALYSIS VX is calculated. IN =Vx/4.
26.

The voltage across 6Ω resistor is __________(a) 7.5V(b) 6.78V(c) 20V(d) 8.5VI got this question in a national level competition.This interesting question is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct choice is (d) 8.5V

Best explanation: Remove the resistor ACROSS which voltage is to be calculated and SHORT circuit it. By using short circuit CURRENT and resistance calculate the current across 6Ω resistor and THEREBY voltage. (In this 10Ω resistor is also short-circuited since 10//0).

27.

Find the current through (5+j4) Ω resistor.(a) 0.9-j0.2 A(b) 0.78-j0.1 A(c) 2.7-j0.5 A(d) 1AThis question was addressed to me at a job interview.This interesting question is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct answer is (a) 0.9-j0.2 A

To elaborate: 1. Remove the 5+j4 Ω branch and calculate THEVENIN’s voltage.

(V= v across 6Ω RESISTOR- v across 8Ω resistor)

2. Calculate Zth. (10//6 and 8//8)

3. Current= (VTH/ (Zth+Z).

28.

Find the Thevenin’s resistance for the network given.(a) 6.75Ω(b) 5.85Ω(c) 4.79Ω(d) 1.675ΩI have been asked this question at a job interview.My query is from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in chapter Techniques of Circuit Analysis of Electric Circuits

Answer»

Right ANSWER is (a) 6.75Ω

The best I can EXPLAIN: Remove all the voltage/current SOURCES and calculate the EQUIVALENT resistance.

29.

Calculate Thevenin’s voltage for the network shown below where the voltage source is 4V.(a) 6V(b) 4.71V(c) 5V(d) 1VI had been asked this question during an online exam.I'm obligated to ask this question of Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in chapter Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT answer is (C) 5V

Best explanation: In the CIRCUIT given, thevenin’s voltage is NOTHING but the open circuit voltage which is Vx. Applying KVL, it is obtained.
30.

If there are five 20V voltage sources in parallel, then in source transformation __________(a) All are considered(b) Only one is considered(c) All are ignored(d) Only 2 are consideredThe question was posed to me in homework.My enquiry is from Source Transformations in chapter Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT ANSWER is (B) Only ONE is considered

The explanation: In parallel, voltages are same. So, only is considered and REST are ignored.
31.

Find the voltage across 24Ω resistor by using Thevenin’s theorem.(a) 8V(b) 9V(c) 1V(d) 6VThe question was posed to me in semester exam.This is a very interesting question from Thevenin and Norton Equivalents,More on Deriving a Thevenin Equivalent topic in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

Right choice is (a) 8V

The explanation: 1. Remove 24Ω resistor and CALCULATE the voltage across the OPEN circuit.

2. Calculate the thevenin’s resistance and by using it, the thevenin’s current.

3. V24Ω=I*R(can also verify by using NODAL analysis).

32.

In source transformation,(a) Voltage sources remain same(b) Current sources remain same(c) Both voltage and current sources undergo change(d) Resistances/Impedances remain sameI have been asked this question in a job interview.My doubt stems from Source Transformations in section Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT option is (d) Resistances/Impedances remain same

The explanation: In source TRANSFORMATION, only the PARTICULAR voltage/current sources change whereas the resistances remain same.
33.

Source transformation technique is mainly based on __________ law.(a) Newton’s(b) Kirchhoff’s(c) Ohm’s(d) Einstein’sI got this question in a job interview.This is a very interesting question from Source Transformations in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Right ANSWER is (c) OHM’s

Easy EXPLANATION: Ohm’s law: V=iR. By USING this, the voltage/ CURRENT sources are reduced.

34.

Find the voltage value Vm in the circuit given below.(a) -3V(b) 3V(c) 2.1V(d) -2.1VThe question was posed to me at a job interview.Query is from Source Transformations in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Right OPTION is (a) -3V

Best explanation: Using source TRANSFORMATION, the voltage source in SERIES with a RESISTOR to be replaced by a current source in parallel with the same resistor and VICE versa.

35.

Source transformation can be used for dependent sources.(a) True(b) FalseI got this question in an online interview.My question is from Source Transformations topic in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Right OPTION is (a) True

For EXPLANATION I would say: Source transformation can be USED for dependent sources. However, the controlling variable must not be TAMPERED with any way since the controlled source operation depends on it.

36.

Using source transformation, calculate vm.(a) 2v(b) -2v(c) 1v(d) -1vThe question was asked by my college professor while I was bunking the class.My question comes from Source Transformations in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

The CORRECT choice is (b) -2v

To explain: Using source transformation, the network is reduced and at last VOLTAGE is OBTAINED.

37.

Calculate the power delivered by the 50V source.(a) 274W(b) 276W(c) 285W(d) 291WI got this question in a job interview.This key question is from Source Transformations topic in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

The correct option is (a) 274W

For explanation I WOULD say: By using source transformation the above network is REDUCED and current in the circuit is found out and later power delivered by 50V source= 50*current in the circuit= 50*5.48A= 274W.

38.

Find the current flowing through 4Ω resistor shown in network below.(a) 1.33A(b) 2.35A(c) 1.66A(d) 2.66AThe question was posed to me during an interview for a job.This key question is from Source Transformations in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Right option is (c) 1.66A

Easiest explanation: By using SOURCE transformation the above network is REDUCED and then by CURRENT DIVISION rule I4Ω= 5*(2/2+4) =1.66A.

39.

If there is a 12A current source in series with 2Ω and in parallel with a 4Ω resistor, then voltage V=?(a) 24V(b) 48V(c) 3V(d) 6VThe question was asked by my college director while I was bunking the class.My enquiry is from Source Transformations in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Right CHOICE is (b) 48V

For explanation I WOULD say: 2Ω resistor is redundant. 12*4=48V.

40.

The value of current source is __________ after replacing the given network with a single current source and a resistor.(a) 70V(b) 60V(c) 90V(d) 80VThis question was addressed to me during a job interview.I'm obligated to ask this question of Source Transformations in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct OPTION is (d) 80V

Best EXPLANATION: In the GIVEN circuit 9Ω RESISTOR has no effect.

10*6=60V, 60V+20V=80V.

41.

Which element(s) has no effect in the given circuit?(a) 7Ω(b) 10Ω(c) Both 7Ω and 10Ω(d) Voltage source.I had been asked this question in a national level competition.I'd like to ask this question from Source Transformations in portion Techniques of Circuit Analysis of Electric Circuits

Answer»

The correct answer is (b) 10Ω

The best explanation: VOLTAGE in SERIES with a RESISTOR in replaced by a CURRENT source but here 10Ω is in parallel. So, it is redundant and has no EFFECT.

42.

If there are two resistors in parallel and in series with a voltage source then ___________(a) Parallel resistor has no effect(b) Series resistor has no effect(c) Both has their respective effects(d) Both has no effect on the voltage sourceThe question was asked in exam.My question is based upon Source Transformations topic in section Techniques of Circuit Analysis of Electric Circuits

Answer»

The CORRECT option is (a) PARALLEL resistor has no effect

Explanation: In source transformation, the voltage source in SERIES with a resistor to be replaced by a current source in parallel with the same resistor and vice versa. So other resistors are redundant and have no effect.

43.

Using source transformation, calculate the voltage.(a) 4.33V(b) 39V(c) 0.230V(d) 36VI got this question during an interview for a job.Question is from Source Transformations in section Techniques of Circuit Analysis of Electric Circuits

Answer»

The CORRECT CHOICE is (B) 39V

Easiest EXPLANATION: V=IR=13*3=39V.

44.

By using source transformation voltage source in series resistor is replaced by __________(a) Voltage source in series with a resistor(b) Current source in parallel with a resistor(c) Voltage source in parallel with a resistor(d) Current source in series with a resistorI have been asked this question at a job interview.I'm obligated to ask this question of Source Transformations topic in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct answer is (b) CURRENT source in PARALLEL with a RESISTOR

For EXPLANATION: In Source transformation, a VOLTAGE source in series with a resistor is replaced by a current source in parallel with the same resistor and vice versa.

45.

Source Transformation is_____________(a) Unilateral(b) Unique(c) Bilateral(d) ComplicatedI have been asked this question in exam.My doubt stems from Source Transformations topic in chapter Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct OPTION is (c) BILATERAL

To explain: In Source transformation, a voltage source in series with a RESISTOR is replaced by a current source in PARALLEL with the same resistor and vice versa. So, it is bilateral.

46.

Which is the best-preferred method to calculate currents flowing in the circuit?(a) Mesh-voltage analysis(b) Node-current analysis(c) Superposition principle(d) Duality principleThis question was posed to me in final exam.This intriguing question comes from The Node-Voltage Method Versus the Mesh-Current Method topic in section Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT answer is (a) Mesh-voltage analysis

To explain: By KVL, currents can be EASILY FOUND out in mesh-voltage method.
47.

When there is a voltage source between two nodes which method is preferred?(a) Mesh-voltage analysis(b) Node-current analysis(c) Supermesh(d) SupernodeThis question was posed to me during an interview.Enquiry is from The Node-Voltage Method Versus the Mesh-Current Method topic in division Techniques of Circuit Analysis of Electric Circuits

Answer» CORRECT CHOICE is (d) Supernode

The best explanation: Supernode is taken into CONSIDERATION when there is a voltage SOURCE n between two nodes.
48.

Determine V1 of the given network.(a) -0.17V(b) 4.83V(c) 5V(d) 2.62VThe question was asked in class test.My query is from The Node-Voltage Method Versus the Mesh-Current Method in division Techniques of Circuit Analysis of Electric Circuits

Answer»

Correct ANSWER is (d) 2.62V

The EXPLANATION is: Supernode: V3-V2=5. Applying KCL at node1 and at supernode gives the EQUATIONS which on solving, REQUIRED voltages are obtained.

49.

There are 6 branches and 2 essential nodes then 3 equations are required to describe a circuit in the mesh-current method.(a) True(b) FalseThe question was asked in examination.My question is from The Node-Voltage Method Versus the Mesh-Current Method in section Techniques of Circuit Analysis of Electric Circuits

Answer»

Right ANSWER is (b) False

The best I can explain: In Mesh-Current METHOD, b-(n-1) EQUATIONS are required to DESCRIBE the CIRCUIT. b= the number of branches and n= the number of essential nodes. So, 6-(2-1) =5.

50.

If there are b branches and n nodes, then how many node-voltage equations are required?(a) n(b) b+1(c) n-1(d) bThe question was posed to me in quiz.This intriguing question comes from The Node-Voltage Method Versus the Mesh-Current Method in chapter Techniques of Circuit Analysis of Electric Circuits

Answer»

The CORRECT answer is (C) n-1

The explanation is: If there are n nodes then n-1 nodal equations are required to DESCRIBE the circuit. BRANCHES do nothing in this case.