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    				| 1. | Find the day of the week on 18July, 1776(leap year) | 
| Answer» Here 1600 years have ‘0’ odd day .......(A). 100years have ‘5’ odd days ..........(B) 75years = (18leap years + 57ordinary years) = (18 × 2 + 57 × 1) = 93odd days = (7 × 13 + 2) = ‘2’ odd days ........(C) Now, the no. of days from 1st January to 18 July, 1776 = 182 + 18 = 200days = (28 × 7 + 4)days = ‘4’odd days ...... (D) Adding (A) + (B) + (C) + (D), We get, 0 + 5 + 2 + 4 = 04odd days Ans. Thursday | |