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Find the displacement ammplitude amplitude of amplitude of particles of air of density `1.2 kg//m^(3)`,if intensity, frequency and speed of sound are `8 xx 10^(-6) w//m^(2), 5000 Hz` and `330 m//s` respectively. |
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Answer» The relation between the intensity of sound and the displacement amplitude is `I = (P_(0^2))/(2rhov)`, `P_(0) = sqrt(2rhovI)` `s_(0) = (P_(0))/(Bk) = (sqrt(2rhogI))/(rhov^(2)pif)v` `= sqrt((I)/(rhov2)) (1)/(pif)` or, `s_(0) = 6.4 nm`. |
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