1.

Find the displacement ammplitude amplitude of amplitude of particles of air of density `1.2 kg//m^(3)`,if intensity, frequency and speed of sound are `8 xx 10^(-6) w//m^(2), 5000 Hz` and `330 m//s` respectively.

Answer» The relation between the intensity of sound and the displacement amplitude is
`I = (P_(0^2))/(2rhov)`,
`P_(0) = sqrt(2rhovI)`
`s_(0) = (P_(0))/(Bk) = (sqrt(2rhogI))/(rhov^(2)pif)v`
`= sqrt((I)/(rhov2)) (1)/(pif)`
or, `s_(0) = 6.4 nm`.


Discussion

No Comment Found

Related InterviewSolutions