Find the distance and displacement of a particle which ismove a circul

1.	Find the distance and displacement of a particle which ismove a circular path when in complete3/4 part of thecircle. Radius of circle is 28.
Answer» ANSWER: perimeter of circle is =2¶r perimeter of circle is = 2× 3.14×28 =175.84 primeter of a circle is 175.84 $1 - \frac{3}{4} = \frac{1}{4}$ $displacement \: = \sqrt{ {r}^{2} } + {r}^{2}$ complete root √r2 +r2 $displacement = \sqrt{2 {r}^{2} }$ $displacement = 2r$ $displacement = 2 \times 28 = 56$ distance =3/4 ×2¶r distance = 3¶r/2 = 131.88