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Find the domain for `f(x)=sin^(-1)((1+x^2)/(2x))` |
Answer» `f(x) = sin^-1((1+x^2)/(2x))` We know `sin theta` lies between `-1` and `1`. `:. -1 le (1+x^2)/(2x) le 1.` `|1+x^2| le 2x` `=>x^2-2|x| + 1 le 0` `=>(|x| - 1)^2 le 0` `=>|x| = 1` `:. x = -1 or x = 1.` `:.` Domain of `f(x)` will be `x in {-1,1}.` |
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