1.

Find the domain for `f(x)=sin^(-1)((1+x^2)/(2x))`

Answer» `f(x) = sin^-1((1+x^2)/(2x))`
We know `sin theta` lies between `-1` and `1`.
`:. -1 le (1+x^2)/(2x) le 1.`
`|1+x^2| le 2x`
`=>x^2-2|x| + 1 le 0`
`=>(|x| - 1)^2 le 0`
`=>|x| = 1`
`:. x = -1 or x = 1.`
`:.` Domain of `f(x)` will be `x in {-1,1}.`


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