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Find the domain of `sec^(-1)(2x+1)`.A. RB. [-1,1]C. `(-oo,-1] cup[0,oo)`D. `[-oo,-1]cup[1,oo)` |
Answer» The domain of `sic^(-1)x is (-infty,-1]cup[1,infty)` Therefore `sec^(-1)(2x+1)`is meaningful if `2x+1ge1 or 2x+1le1` `rarr 2xge0 or 2xle-2` `rarr xge0 or xle-1` `rarrx(-infty,-1]cup[0,infty)` Hence the domain of `sec^(-1)(2x+1)is(-infty,-1]cup[0,infty)` |
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