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Find the electric field due to charge density of 1/18 and distance from a point P is 0.5 in air(in 10^9 order)(a) 0(b) 1(c) 2(d) 3This question was posed to me in an interview for internship.Origin of the question is Method of Images in section Electrostatic Boundary Value Problem of Electromagnetic Theory

Answer» RIGHT choice is (c) 2

The best I can explain: The ELECTRIC field for this case is given by, E = ρl/2πεd. PUT ρl = 1/18 and d = 0.5. We get E = 2 X 10^9 UNITS.


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