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Find the electric field due to charge density of 1/18 and distance from a point P is 0.5 in air(in 10^9 order)(a) 0(b) 1(c) 2(d) 3This question was posed to me in an interview for internship.Origin of the question is Method of Images in section Electrostatic Boundary Value Problem of Electromagnetic Theory |
Answer» RIGHT choice is (c) 2 The best I can explain: The ELECTRIC field for this case is given by, E = ρl/2πεd. PUT ρl = 1/18 and d = 0.5. We get E = 2 X 10^9 UNITS. |
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