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Find the electric field if the surface density at the boundary of air is 10^-9.(a) 12π(b) 24π(c) 36π(d) 48πI had been asked this question in an online interview.My question is taken from Boundary Conditions topic in division Electric Fields in Material Space of Electromagnetic Theory

Answer»

Right OPTION is (C) 36π

The best I can EXPLAIN: It is the conductor-free space boundary. At the boundary, E = ρ/εo. Put ρ = 10^-9 and εo = 10^-9/36π. We GET E = 36π units.



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