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Find the electric field intensity at 10cm away from a point charge of 100 esu.(a) 1 dyne/esu(b) 10 dyne/esu(c) 100 dyne/esu(d) 9*10^9 dyne/esuThe question was asked in examination.This interesting question is from Electric Field in section Charges and Fields of Physics – Class 12 |
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Answer» The CORRECT option is (a) 1 dyne/esu |
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