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Find the entropy change when 90 g of `H_(2)O` at `10^(@)`C was converted into steam at `100^(@)`C. [Given `C_(P)(H_(2)O)=75.29 JK^(-1)mol^(-1) and Delta H_("vap")=43.932 JK^(-1)mol^(-1)`] |
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Answer» `H_(2)O(I) rarr H_(2)O(I) hArr H_(2)O("vap")` `10^(@)C rarr 100^(@)C rarr 100^(@)C` `Delta S = underset(283)overset(373)int nC_(P)dIn T+(Delta H_("vap"))/(T_(3))xx` No. of moles `5 xx 2.303 xx 75.29"log"(373)/(283)+(43.932 xx 10^(3))/(373)xx5` = 866.96 log 1.318 + 588.9 = 692.84 `JK^(-1)` |
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