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Find the equation of a circle whose centre is (2, 3) and radius is 5. |
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Answer» Here centre `(h,k) = (2,3)`, and radius `a=5` `:.` Equation of circle `(x-h)^(2)+(y-k)^(2)=a^(2)` `rArr (x-2)^(2) + (y-3)^(2)=5^(2)` `rArr x^(2)-4x+4 y^(2)-6y +9 = 25` `rArr x^(2)+y^(2)-4x -6y - 12=0` |
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