1.

Find the equation of a circle whose centre is (2, 3) and radius is 5.

Answer» Here centre `(h,k) = (2,3)`, and radius `a=5`
`:.` Equation of circle
`(x-h)^(2)+(y-k)^(2)=a^(2)`
`rArr (x-2)^(2) + (y-3)^(2)=5^(2)`
`rArr x^(2)-4x+4 y^(2)-6y +9 = 25`
`rArr x^(2)+y^(2)-4x -6y - 12=0`


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