Find the equation of all the lines having slope 0 which are tangent to the curve y=6x^2-7x.(a) \(\frac{24}{49}\)(b) –\(\frac{24}{49}\)(c) \(\frac{49}{24}\)(d) –\(\frac{49}{24}\)This question was addressed to me during an interview for a job.This intriguing question originated from Derivatives Application in chapter Application of Derivatives of Mathematics – Class 12

Find the equation of all the lines having slope 0 which are tangent to

1.	Find the equation of all the lines having slope 0 which are tangent to the curve y=6x^2-7x.(a) \(\frac{24}{49}\)(b) –\(\frac{24}{49}\)(c) \(\frac{49}{24}\)(d) –\(\frac{49}{24}\)This question was addressed to me during an interview for a job.This intriguing question originated from Derivatives Application in chapter Application of Derivatives of Mathematics – Class 12
Answer» Right answer is (d) –\(\FRAC{49}{24}\) Explanation: GIVEN that, y=6x^2-7x \(\frac{dy}{dx}\)=12x-7 It is given that the slope of tangent is 0 ∴12x-7=0 ⇒X=\(\frac{7}{12}\) ∴ y]x=\(\frac{7}{12}\)=6(\(\frac{7}{12}\))^2-7(\(\frac{7}{12}\)) 6(\(\frac{49}{144})-\frac{49}{12}=49(-\frac{1}{24})=-\frac{49}{24}\)

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