Find the equation of circle which pass through (5, 9) and center at (2, 5).(a) x^2+y^2+4x-10y+4=0(b) x^2+y^2-4x-10y+4=0(c) x^2+y^2+4x+10y+4=0(d) x^2+y^2+4x-10y-4=0I have been asked this question by my school principal while I was bunking the class.Origin of the question is Conic Sections topic in section Conic Sections of Mathematics – Class 11

Find the equation of circle which pass through (5, 9) and center at (2

1.	Find the equation of circle which pass through (5, 9) and center at (2, 5).(a) x^2+y^2+4x-10y+4=0(b) x^2+y^2-4x-10y+4=0(c) x^2+y^2+4x+10y+4=0(d) x^2+y^2+4x-10y-4=0I have been asked this question by my school principal while I was bunking the class.Origin of the question is Conic Sections topic in section Conic Sections of Mathematics – Class 11
Answer» Right CHOICE is (b) x^2+y^2-4x-10y+4=0 Explanation: Equation of circle with center at (a, b) and radius R UNITS is (x-a)^2 + (y-b)^2 = r^2 (5-2)^2 + (9-5)^2 = r^2 => r^2=3^2+4^2 => r=5. So, equation of circle is (x-2)^2+(y-5)^2=5^2 => x^2+y^2-4x-10y+4=0.

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