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Find the equation of circle whose : (i) radius is 5 and centre is (3,4). (ii) radius is `sqrt(5)` and centre is (0.2). (iii) radius is `sqrt(a^(2)+b^(2))` and centre is (a,b). (iv) radius is r and centre is `(rcostheta,rsintheta)`. (v) radius is `sqrt(a^(2)sec^(2)theta+b^(2)tan^(2)theta)` and centre is `(asectheta,btantheta)`. |
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Answer» Correct Answer - (i) `x^(2)+y^(2)-6-8y=0` , (ii) `x^(2)+y^(2)-4y-1=0` (iii) `x^(2)+y^(2)-2ar-2by=0` (iv) `x^(2)+y^(2)-2rcostheta*x-2rsintheta*y=0` (v) `x^(2)+y^(2)-2axsectheta-2bytantheta=0` |
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