Find the equation of circle with center at (2, 5) and radius 5 units.(a) x^2+y^2+4x-10y+4=0(b) x^2+y^2-4x-10y+4=0(c) x^2+y^2+4x+10y+4=0(d) x^2+y^2+4x-10y-4=0This question was posed to me during an interview for a job.This interesting question is from Conic Sections in portion Conic Sections of Mathematics – Class 11

Find the equation of circle with center at (2, 5) and radius 5 units.(

1.	Find the equation of circle with center at (2, 5) and radius 5 units.(a) x^2+y^2+4x-10y+4=0(b) x^2+y^2-4x-10y+4=0(c) x^2+y^2+4x+10y+4=0(d) x^2+y^2+4x-10y-4=0This question was posed to me during an interview for a job.This interesting question is from Conic Sections in portion Conic Sections of Mathematics – Class 11
Answer» The correct option is (B) x^2+y^2-4x-10y+4=0 The best I can explain: EQUATION of circle with center at (a, b) and RADIUS R UNITS is (x-a)^2+(y-b)^2=r^2 So, equation of circle is (x-2)^2+(y-5)^2=5^2 => x^2+y^2-4x-10y+4=0.

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