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Find the equation of ellipse whose vertices are `(0,pm13)` and foci `(0,pm5)`. |
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Answer» The vertices and foci of ellipse are on y-axis. `:." "bgta` Now co-ordinates of the vertices = `0,pmb)` and co-ordinates of foci `=(0,pmbe)` `:.` b=13 and be=5 `:." "e=(5)/(13)` and `a^(2)=b^(2)(1-e^(2))` `=169(1-(25)/(169))=144` `:.` Therefore, the equation of ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1` `rArr" "(x^(2))/(144)+(y^(2))/(169)=1`. |
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