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Find the equation of Hyperbola satisfying the following conditions:Foci `(pm3sqrt(5),0)` the latus rectum is of length 8. |
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Answer» Here, `ae=3sqrt(5)` and `(2b^(2))/(a)=8` `rArrb^(2)=4a` `rArra^(2)(e^(2)-1)=4a` `rArra^(2)e^(2)-1a^(2)=4a` `rArr45-a^(2)=4a` `rArra^(2)+4a-45=0` `rArr(a+9)(a-5)=0` `rArra=-9anda=5` But `a!=-9` `:." "a=5` `and" "b^(2)=4a=4xx5=20` Therefore, equation of hyperbola `(x^(2))/(25)-(y^(2))/(20)=1rArr4x^(2)-5y^(2)=100` |
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