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Find the equation of parabola whose focus is (2,0) and equation of directrix is x=-2. |
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Answer» Equation of directrix x=-2 `rArr" "x+2=0` Let P(x, y) be any point on the parabola. Therefore, from the definition of parabola distance of from focus = perpendicular distance from p to directrix. `rArr" "sqrt((x-2)^(2)+(y-0)^(2))=x+2` `rArr" "(x-2)^(2)+y^(2)=(x+2)^(2)` `rArr" "y^(2)=8x`. |
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