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Find the equation of the circle with centre :`(1/2,1/4)` and radius `1/(12)` |
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Answer» Centre `-=((1)/(2),(1)/(4))` and radius `(1)/(12)` unit. `:.` Equation of circle, `(x-h)^(2)+(y-k)^(2)=r^(2)` `rArr" "(x-(1)/(2))^(2)+(y-(1)/(4))^(2)=((1)/(12))^(2)` `rArr" "((2x-1)^(2))/(4)+((4y-1)^(2))/(16)=(1)/(144)` `rArr" "36(4x^(2)-4x+1)+(16y^(2)-8y+1)=1` `rArr" "144x^(2)-144x+36+144y^(2)-72y+9-1=0` `rArr" "144x^(2)+144y^(2)-144x-72y+44=0` `rArr" "36x^(2)+36y^(2)-36x-18y+11=0` |
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