Find the focal length of the leans which forms a virtual image at 50cm

1.	Find the focal length of the leans which forms a virtual image at 50cm of an object placed at 20cm from that leans. Also give the natural of leans
Answer» According to sign convention , Image distance (V) = 50 CM Object distance (u) = -20 cm We know that , the lens formula is given by $\boxed{ \sf{ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} }}$ Thus , 1/f = 1/50 - (-1/20) 1/f = 1/50 + 1/20 1/f = 70/1000 f = 100/7 f = 14.2 cm The POSITIVE value of f shows the NATURE of lens is convex ★ The FOCAL length of convex lens is 14.2 cm

Find the focal length of the leans which forms a virtual image at 50cm of an object placed at 20cm from that leans. Also give the natural of leans

Answer»

According to sign convention ,

Image distance (V) = 50 CM
Object distance (u) = -20 cm

We know that , the lens formula is given by

$\boxed{ \sf{ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} }}$

Thus ,

1/f = 1/50 - (-1/20)

1/f = 1/50 + 1/20

1/f = 70/1000

f = 100/7

f = 14.2 cm

The POSITIVE value of f shows the NATURE of lens is convex

★ The FOCAL length of convex lens is 14.2 cm

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Find the focal length of the leans which forms a virtual image at 50cm of an object placed at 20cm from that leans. Also give the natural of leans​

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Find the focal length of the leans which forms a virtual image at 50cm of an object placed at 20cm from that leans. Also give the natural of leans