Find the force required to move a train of mass `5000` quintal up an incline of `1` in `50` with an acceleration of `2m//s^(2)` Take force of friction = 0.2 N quintal and `g = 10ms^(-2)`.

Find the force required to move a train of mass `5000` quintal up an i

1.	Find the force required to move a train of mass `5000` quintal up an incline of `1` in `50` with an acceleration of `2m//s^(2)` Take force of friction = 0.2 N quintal and `g = 10ms^(-2)`.
Answer» Correct Answer - `1.101 xx 10^(6)` . Here, `m = 5000 "quintals" = 5 xx 10^(5)kg` `sin theta = 1//50, a = 2m//s^(2) F = 0.2N//quintal` `0.2 xx 5000 = 10^(3) N` Total force required `f = mg sin 0 + F + ma` `f = 5 xx 10^(5) xx 10 xx (1)/(5) + 10^(3) + 5 xx 10^(5) xx 2` `= 10^(5) + 10^(3) + 10^(6) = 10^(6) (0.1 + 0.001 + 1)` `f = 1.101 xx 10^(6)N` .

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Find the force required to move a train of mass `5000` quintal up an incline of `1` in `50` with an acceleration of `2m//s^(2)` Take force of friction = 0.2 N quintal and `g = 10ms^(-2)`.

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