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Find the gate to source voltage for voltage divider having R1=R2=2KΩ and VDD=12V, ID=1mA and RS=4KΩ?(a) 3V(b) 2V(c) 0V(d) 1VThis question was posed to me by my school principal while I was bunking the class.My question is based upon Biasing the FET in portion Field-Effect Transistors of Electronic Devices & Circuits |
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Answer» CORRECT answer is (b) 2V Easy explanation: VG = R2×VDD/R1+R2 =>VG=2×12/4 =>VG=6V =>VGS=VG-ID RS =>VGS=2V. |
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