1.

Find the general solution of the following differential equation:\(\frac{dy}{dx}\) + y = 1 (y ≠ 1)

Answer»

\(\frac{dy}{dx}\) = 1 - y

\(\frac{1}{1-y}dy\) = dx

Integrating on both sides

\(\int\frac{1}{1-y}dy\) = \(\int{dx}\)

⇒ log |1 - y| = x + c



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