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Find the general solution of the following differential equation:\(\frac{dy}{dx}\) + y = 1 (y ≠ 1) |
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Answer» \(\frac{dy}{dx}\) = 1 - y \(\frac{1}{1-y}dy\) = dx Integrating on both sides \(\int\frac{1}{1-y}dy\) = \(\int{dx}\) ⇒ log |1 - y| = x + c |
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