1.

Find the general solution of the following differential equation:\(\frac{dy}{dx}\) = (1 + x)(1 + y2)

Answer»

\(\frac{1}{1+y^2}dy\) = (1 + x)dx

Integrating on both sides

\(\int\frac{1}{1+y^2}dy\) = \(\int(1+x)dx\)

⇒ tan-1y = x + \(\frac{x^2}2\) + c



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