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Find the general solution of the following differential equation:\(\frac{dy}{dx}\) = \(\frac{x}{(x^2+1)}\) |
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Answer» dy = \(\frac{x}{x^2+1}\)dx Multiply and divide 2 in numerator and denominator of RHS, y = \(\frac{1}2\).\((\frac{2x}{x^2+1}dx)\) Integrating on both sides y = \(\frac{1}2\).log (x2 + 1) + c |
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